(x+7)(x^2-5x+3)=0

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Solution for (x+7)(x^2-5x+3)=0 equation: 


Simplifying
(x + 7)(x2 + -5x + 3) = 0

Reorder the terms:
(7 + x)(x2 + -5x + 3) = 0

Reorder the terms:
(7 + x)(3 + -5x + x2) = 0

Multiply (7 + x) * (3 + -5x + x2)
(7(3 + -5x + x2) + x(3 + -5x + x2)) = 0
((3 * 7 + -5x * 7 + x2 * 7) + x(3 + -5x + x2)) = 0
((21 + -35x + 7x2) + x(3 + -5x + x2)) = 0
(21 + -35x + 7x2 + (3 * x + -5x * x + x2 * x)) = 0
(21 + -35x + 7x2 + (3x + -5x2 + x3)) = 0

Reorder the terms:
(21 + -35x + 3x + 7x2 + -5x2 + x3) = 0

Combine like terms: -35x + 3x = -32x
(21 + -32x + 7x2 + -5x2 + x3) = 0

Combine like terms: 7x2 + -5x2 = 2x2
(21 + -32x + 2x2 + x3) = 0

Solving
21 + -32x + 2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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